Type the correct answer in the box. Write your answer as a reduced fraction, using / for the fraction bar. A six-sided fair die is rolled 4 times in a row. The probability of getting a 4 only on the last trial is

Step-by-step explanation:

P(4 only on the last roll) = P(not 4 on first roll) and P(not 4 on the second roll) and P(not 4 on the third roll) and P(4 on the last roll)

in probability and = multiplication

P( not roll a 4) = 1 - P(roll a 4)

P(4 only on the last roll) = 1-P(4) * 1-P(4)  *1-P(4) * P(4)

P(4) = 1 (1 time# 4 appears on the die)/6 (#of possible outcomes 1,2,3,4,5,6)

P(4 only on the last roll) = 1-(1/6) * 1-(1/6)  *1-(1/6) * (1/6)

P(4 only on the last roll) =(5*5*5*1)/(6*6*6*6) = 125/1296

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )