Find the area of the surface generated when the given curve is revolved about the given axis. 5x^1/3

Step-by-step explanation:

The curve x = f(y)

The area of the surface around the y-axis from y = a → y = b is:

From the given curve:

; assuming the region bounded by the curve is 0 ≤ y ≤ 1

So;

5x = y³

The differential of the above equation Is:

Now, we have the area of the surface produced around the curve through the y axis from the region y = 0 to y = 1

∴

Let make

It implies that:

when y = 0 ;

u = 5

when y = 1;

∴

The equation can be written as:

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)