What is the equation of a line that contains the point (2,-5) and is parallel to the line y=3x-4

y = 3x - 11

Step-by-step explanation:

Parallel lines have the same slope so the relationship of x and y stays the same only the constant, b,  changes

y = 3x + b

plug in point (2, -5) to find "b"

-5 = 3(2) + b

-5 = 6 + b

subtract 6 from both sides

-11 = b

The equation is

y = 3x - 11

(2 , -5) are the points

then y =3x-x,let 4 be x

substitute 2&-5 in the line

-5 =3(2)-x

-5=6-x

-x=6 +5

=11

:x =-11

y=3x - (-11)

y =3x+11

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

3,000,540

step-by-step explanation: