The growth of 100 young trees near a river is given below. At most 50 yards from the river (Event Y) More than 50 yards from the river (Event Z) Grew at most 3 feet during the year (Event E) 10 35 Grew more than 3 feet during the year (Event F) 50 5 If a tree grew more than 3 feet during the year, how much more likely is it that the tree was at most 50 yards from the river? Show all of your work.

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation:

unless if u could do my questions, if not i wouldn't want to

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.