Suppose that a company claims that its air fresheners last 23 days, on average. You take many large samples, and find, each time, that the mean
number of days of the sample is outside the 95% confidence interval. Based
on this information alone, which of the following is probably not the mean
number of days that the company's air fresheners last?
O A. 19
O B. 17
O C. 23
• D. 21

Step-by-step explanation:

This is the answer because it is subtracted so that you get the answer

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

96 39 cause 135 -96=39 im smart (i used a calculater)