What is the solution to the system of equations

The solution to this system of equations is x = 8, and y = -9

Step-by-step explanation:

Firstly we need to use the first equation to represent "x" in terms of "y", so we do the following...

Now we take the second equation and replace "x" with an equal value in terms of "y" which we know from the previous equation, and just solve for "y".

After we found the value of "y" we can find the value of "x" by using any of the two equations, we just have put "-9" instead of "y". For example...

Now we know that the solution to this system of equations is x = 8, and y = -9

10.4 inches

step-by-step explanation:

2x2x2.6

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)