I will give u brainliest if u actually help me explain this in ur own words :,( When a complex number is in the denominator, why is it necessary to multiply by the conjugate?

It just makes doing things (like adding and subtracting other numbers) easier if the denominator is a real number. Other than that we just do it out of tradition

This step is done to make the denominator go from a complex number in the form a+bi into a purely real number in the form a^2+b^2 (where 'a' and b are any real numbers).

This is because multiplying a+bi with its conjugate a-bi leads to the following steps

(a+bi)(a-bi)

(a)^2 - (bi)^2 ... difference of squares

a^2 - b^2*i^2

a^2 - b^2*(-1) recall that i^2 = -1

a^2 + b^2

So for example, if your denominator was 2+3i, then you'd multiply that by the conjugate 2-3i and you'd end up with the final denominator of 2^2+3^2 = 4+9 = 13. In this case, a = 2 and b = 3.

Note: make sure to multiply both top and bottom by a-bi (not just the denominator).

answer: y=0 if that is what u r looking for

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.