A rectangle has a length that is 8 inches more than its width, w. The area of the rectangle is 65 square inches. so i have to find the length. I need help ;-;

13in

Step-by-step explanation:

Let the width be w

The length will be 8+w

(8+w)(w)=65

8w+w^2=65

w^2+8w-65

Use quadratic equation formula.

You will get two answers

w=5 or w= -13

Pick the answer that is more sensible.

It cannot be a negative number; hence use 5in

5in+8in= 13in

13 and 5 are the lengths

Step-by-step explanation: if its 8 inches more on one side than the other then it goes like this 9x1 is 9. 10x2 is 20. 11x3 is 33. 12x4 is 48. 13x5 is 65. 13x5 is the rectangle.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>