A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of individuals who had been taking the drug is questioned; of them found relief from depression. Based upon this, compute a confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limit and upper limit of the confidence interval.

The answer is "(0.7322,0.8234)".

Step-by-step explanation:

please find the complete question in the attached file.

The sample has 225 persons, thus n = 225. Of these 175 people, the sample proportion was decreased through depression

So z-value is 1.645 for an interval of 90%. The 90% trust interval will be

The confidence interval therefore is 90% (0.7322,0.8234).

The 90% confidence interval's lower limit is 0.7322.

The 90% confidence interval is 0.8234 at its upper limit.

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y