Chuin has 18 coins in his pocket. He has nickels and dimes that total $1.45. How many nickels and how many dimes does he have? Write and solve a system of equations to find the answer. A. 10 Nickles, 8 dimes
B. 9 nickles, 9 dimes
C. 8 nickles, 10 dimes
D. 7 nickles, 11 dimes

D

Step-by-step explanation:

Let n represent the number of nickels and d represent the number of dimes Chuin has.

Since Chuin has a total of 18 coins in his pocket, the sum of the number of nickels and dimes must total 18. So:

The total worth of the coins is $1.45. Since each nickel is worth $0.05 and each dime is worth $0.10:

Solve the system. We can use elimination (you can use substitution if you prefer, it works just as perfect!). First, multiply both sides of the second equation by 10:

Next, we can multiply the first equation by negative one:

Add the two equations together:

Simplify:

Divide both sides by -0.5. So:

Chuin has seven nickels.

Using the first equation again, substitute n for 7 and solve for d:

Therefore, Chuin has seven nickels and 11 dimes.

Our answer is D.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: