Need help with this.

m ∠S = 43°

Step-by-step explanation:

Exterior angle = Sum of opposite interior angles

(6x)° = 77° + (2x + 3)°

6x = 77 + 2x + 3

6x - 2x = 77 + 3

4x = 80

x = 20

m ∠S = (2x + 3)° = 2(20) + 3 = 40 + 3 = 43°

∠ S = 43°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ PQR is an exterior angle of the triangle, then

6x = 77 + 2x + 3 ( subtract 2x from both sides )

4x = 80 ( divide both sides by 4 )

x = 20

Then

∠ S = 2x + 3 = 2(20) + 3 = 40 + 3 = 43°

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0