A+b+c=68
a-b=5
b:c=3

a, b,c=?

a = 32

b= 27

c = 9

Step-by-step explanation:

a= 5+ b from the second equation

c= b/3 from the third equation

substitute the above equations to the first equation then solve for b your answer will be 27

substitute the value of b in the second equation you will solve for a

perform the same substitution to the third equation you will get the answer for c

Step-by-step explanation:

a-b=5<=>a=5+b (1)

b:c=3<=>b=3c (2)

a+b+c=68<=>5+b+3c+c=68<=>5+3c+3c+c=68

<=>7c=63<=>c=9

Fill in (2), we have b=3c=3.9=27

and in (1), we have a=5+b=5+27=32

So, a=32, b=27, c=9

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!