An animal shelter has enough pens for x small dogs and y large dogs, and can hold up to 36 dogs at a time. It costs the shelter $12 a week to keep a large dog and $7 a week to keep a small dog. The shelter must keep its weekly costs under $350. Which system of inequalities can be used to represent this situation?

7x+12y<350

Step-by-step explanation:

7 times each small dog (x) plus 12 times each large dog (y) needs to be less than (<) 350

35x 3= 105

step-by-step explanation:

35+35= 70   70 + 35= 105

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube