What is the solution to the following system of equations? [3x-2y = 12
16x-4y = 24
O It has infinitely many solutions.
It has no solution.
It has one solution (2, -3).
It has one solution (4,0).

(0, -6)

Step-by-step explanation:

Given the following systems of linear equations;

3x - 2y = 12 equation 1

16x - 4y = 24 equation 2

We would solve for the solution using the elimination method;

Multiplying eqn 1 by 2, we have;

2 * (3x - 2y = 12)

6x - 4y = 24

16x - 4y = 24

Subtracting the two equations, we have;

(6x - 16x) + (-4y -[-4y]) = (24 - 24)

-10x - 0 = 0

-10x = 0

x = -0/10 = 0

Next, we would find the value of y;

3x - 2y = 12

3(0) - 2y = 12

0 - 2y = 12

-2y = 12

y = -12/2

y = -6

Check:

3x - 2y = 12

3(0) - 2(-6) = 12

0 - (-12) = 12

12 = 12

Note: the options provided for this questions are incorrect or inappropriate.

i can you with this sweetie!

step-by-step explanation:

i believe the correct answer is b.