Mathematics, 21.06.2021 01:00 Crxymia
7(x + y) ex2 β y2 dA, R where R is the rectangle enclosed by the lines x β y = 0, x β y = 7, x + y = 0, and x + y = 6
Answers: 1
Β , Β 
![j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right]](/tpl/images/1379/9691/de8f1.png)
![j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right]](/tpl/images/1379/9691/c0629.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du](/tpl/images/1379/9691/6bf3b.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du](/tpl/images/1379/9691/50c47.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0](/tpl/images/1379/9691/eae67.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)]](/tpl/images/1379/9691/96cad.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}]](/tpl/images/1379/9691/e2dc7.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}]](/tpl/images/1379/9691/8c46c.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}]](/tpl/images/1379/9691/79b21.png)
![\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}]](/tpl/images/1379/9691/75dec.png)
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7(x + y) ex2 β y2 dA, R where R is the rectangle enclosed by the lines x β y = 0, x β y = 7, x + y =...
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