The equation of the circle having center (5, 4) and touching y-axis is A. x 2 + y2 – 10x – 8y + 25 = 0

B. x 2 + y2 – 5x + 4y + 8 = 0

C. x 2 + y2 – 5x + 4y + 8 = 0

D. x 2 + y2 – 42 – 5y + 10 = 0

None Of the Above.

Step-by-step explanation:

As we know that the general equation of circle is

( x - h )^2 + ( y - k )^2 = r^2

putting h=5 and k= 4 and r= 5

x² + 25 - 10x + y² +16 - 8y = 25

x² + y² - 10x - 8y + 16 = 0 is the answer.

I got this answer from Gauthmath its a really cool new app having solutions from tutor. Just scan questions and you can get answers from tutor.

you can get the app on Play Store or App Store. Or you can join their discord (Gauthmath_Homeworkhelp).

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

greater than one

step-by-step explanation: