Flying against the wind a jet travels 1590 miles in 3 hours flying with the wind the same jet travels 8240 miles in 8 hours. What is the rate of the j et in still air and what is the rate of the wind?

See explanation

Step-by-step explanation:

From the information given, the following can be deduced:

Let rate of jet in still air be J

Let rate of wind be W

The formula for distance:

d = rt

Therefore, r = d/t

When, flying against the wind, then the Jet flies at a rate of J - W which will be:

= 1590mi/3hrs

= 530mph

When flying with the wind the jet will fly at a rate of J+W which will be:

= 8240mi/8hrs

= 1030 mph

Their average rate will be:

J = (530+1030)/2

= 1560/2

J = 780 mph

Since J - W = 530

Therefore, so

780 - W = 530

W = 780 - 530

W = 250 mph

The Jet in still air flies at a rate of 780 mph and the wind speed is 250 mph

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

step-by-step explanation: