A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. y=-16x^2+119x+57

Time required to hit the ground is 7.9 s.

Step-by-step explanation:

The height of the rocket is given by

For the time to hit the ground, put y = 0

Time cannot be negative, so time to hit the ground is 7.9 s.

sine

step-by-step explanation:

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!