Suppose that γ is an angle with csc γ = -11/10 and γ is not in the third quadrant. Compute the exact value of cot γ. You do not have to rationalize the denominator.

Draw your right triangles.

sin(g) = -3/4: you need to draw the point (x, y) such that y = -3, x < 0, and x2 + (-3)2 = 42

Then cos(g) = x/4, tan(g) = -3/x, csc(g) = -4/3, sec(g) = 4/x, and cot(g) = -x/3

The others are done similarly: use the info given to figure out the (x, y) point, and derive trig ratios from them,

idk

step-by-step explanation: