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Mathematics, 16.06.2021 19:40 mayb3imdr3aming

Cho hình chóp S. ABCD có đáy là hình chữ nhật, AB= 2a, AD bằng a căn 3. Tam giác SAB cân tại S nằm trong mặt phẳng vuông góc với đáy. Cạnh bên SD hợp với đáy một góc 45 độ. Khoảng cách giữa SA và BD tính theo a

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