Use quadratic formula to find the solutions to the quadratic equation 2x^2-3x+6=0

2x² - 3x + 6 = 0

a = 2 b = -3 c = 6

delta = b² - 4ac = 9 - 4.2.6 = -39

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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