A clock. The short hand points just after 2 and the long hand points to the third tick mark after 2. A clock. The short hand points just after 2 and the long hand points to the third tick mark after 2. A clock. The short hand points about halfway between 8 and 9 and the long hand points to the second tick mark after 7. A clock. The short hand points about halfway between 8 and 9 and the long hand points to the second tick mark after 7. How much time has passed from the first clock to the second clock

The correct answer is - 6 hours 24 minutes.

Step-by-step explanation:

Given:

Clock A - The short hand points just after 2 and the long hand points to the third tick mark after 2 = 2'O clock and thirteen minutes.

Clock B - The short hand points about halfway between 8 and 9 and the long hand points to the second tick mark after 7 = 8'O clock and 37 minutes.

Solution:

The time difference between two clocks can be calculated by subtracting the time of clock A from the time of clock B.

time passed = 8'O clock and 37 minutes - 2'O clock and thirteen minuts

= 6 hours and 24 minutes.

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4