Solve the equation by factoring. 2x^2=8x

x= 0    x=4

Step-by-step explanation:

2x^2=8x

Subtract 8x from each side

2x^2   -8x=8x-8x

2x^2 - 8x =0

Factor 2x

2x( x-4) =0

Using the zero product property

2x =0   x-4 =0

x= 0    x=4

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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