The equation of a linear function in point-slope form is y-y1=m(x-x1). Harold correctly wrote the equation y=3(x-7) using a point and the slope. Which point did Harold use ?

(7, 0).

Step-by-step explanation:

We have   y =  3(x - 7)

y = 3x - 21

Point-slope form is

y - y1 = 3(x - x1)

y  -  y1 = 3x - 3x1

Comparing this to the equation y = 4x - 21 we see that y1 = 0 and x1 = 7.

560

hope this : )