Adjust the interior angles for the traverse in Assignment 5. Recalculate azimuths, and adjust the latitudes and departures using the compass (Bowditch) rule. Report final adjustments to the nearest 0.01 feet but make sure that the traverse closes. Calculate the area enclosed by the adjusted traverse (nearest 100 ft2 ).

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

What is the perimeter of a rectangular building that is 80 feet wide and 140 feet deep?

After t seconds, a ball tossed in the air from the ground level reaches a height of h feet given by the equation h = 144t-16t^2. after how many seconds will the ball hit the ground before rebounding?