A paint shop mixes colours to the customers taste. To make 1 litter of base white, 2 milliliters of B and 0,25 milliliter of C. how much of each component will he use for mixture containing 750 litres of base white? write each answer in litres.​

Mixing quantity of B = 1.5 liter

Mixing quantity of C = 0.1875 liter

Step-by-step explanation:

Given:

Mixing ratio;

1 liter white base , 2 milliliter of B , 0.25 milliliter of C

Find:

Mixing quantity in 750 liters

Computation:

2 milliliter of B = 0.002 L

0.25 milliliter of C = 0.00025 L

Mixing quantity of B = 750 x 0.002

Mixing quantity of B = 1.5 liter

Mixing quantity of C = 750 x 0.00025

Mixing quantity of C = 0.1875 liter

46 dollars is the answer.

step-by-step explanation:

6*6 = 36,         36+10=46