Cho ánh xạ tuyến tính f: R³⇒R³ và hai cơ sở của R³ B={b1=(1;3;3),b2=(-3;6;5),b3=(1;2;2 )}
C={c1=(2;0;3),c2=(-5;-1;-5).c3=(1;0 ;1)}
Biết f(b1)=(-5;6;4), f(b2)=(-8;5;2). f(b3)=(=9;-2;-5)
a) tìm ma trận A=[f]E3 từ đó suy ra biểu thức của f(x1;x2;x3)
b tìm ma trận [f]B
c từ [f]B tính ma trận[f]CB

hi! i think the answer is 1/2 : )

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two