Annabelle is going to see a movie and is taking her 4 kids. Each movie ticket costs $and there are an assortment of snacks available to purchase for $3 each. How much total money would Annabelle have to pay for her family if she were to buy 6 snacks for everybody to share? How much would Annabelle have to pay if she bought x snacks for everybody to share? Cost for 6 snacks:
Cost for x snacks:

(a) $83 for 6 snacks

(b) --- for x snacks

Step-by-step explanation:

Given

Let:

--- per individual

--- per individual

Solving (a): Amount for 6 snacks

The amount paid (y) is:

---- because she bought 6 snacks

---- Annabelle and the 4 kids.

So:

Solving (b): For x snacks

The amount paid (y) is:

---- because she bought x snacks

4

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2