Three Bell ringing constituency in intervals of 30,36 and 45 minutes respectively. At what time will they ring together again if they ring simultaneously at 8:00 a. M.​

The bells will ring simultaneously at 11.00 a.m

Step-by-step explanation:

Firstly, what we have to do here is to get the lowest common multiple the three numbers

The numbers are the given minutes

These are 30,36 and 45 minutes

The lowest common multiple of these three is 180 minutes

Now, we convert this to hours

60 minutes = 1 hour

180 minutes = x hours

x * 60 = 180 * 1

x = 180/60

x = 3 hours

If we added this to 8 am, we have 8 + 3 = 11 a.m

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it