What happens if simultaneous Equations have two of the same variable like below? How would I solve it? 6A + 4B + 5C = 390
6A + 4B + 5.75C = 405​

C = 20

Step-by-step explanation:

What happens if simultaneous Equations have two of the same variable like below? How would I solve it?

6A + 4B + 5C = 390

6A + 4B + 5.75C = 405​

Step 1

We solve for C first

6A + 4B + 5C = 390Equation 1

6A + 4B + 5.75C = 405​... Equation 2

We substract Equation 1 from Equation 2

0.75C = 15

C = 15/0.75

C = 20

i think this could be a possible answer (1 / 84) -1

good luck! : d

answer: (x+2) (x+3) are the binomials for your question : )