If y=-4x + 1 were changed to y = -2x + 6, how would the graph of the new line compare with the first one?
A. The new graph would be less steep than the original graph, and
the y-intercept would shift down 2 units.
B. The new graph would be steeper than the original graph, and they
intercept would shift up 5 units.
C. The new graph would be steeper than the original graph, and the y-
intercept would shift down 2 units.
D. The new graph would be less steep than the original graph, and
the y-intercept would shift up 5 units.

answer: c i think

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: your gay

step-by-step explanation:

you dont know math