Joseph borrows $10000 from his sister Katie at an annual interest rate of 10%. If the interest is compounded twice a year, how much does he owe after 12 months? Give your answer in dollars.

A  =  P  ( 1  + r / n)  ^( t * n)

where

A  =  the amt  owed

P  = amt borrowed

r  = the  interest  rate  as a decimal

n =  the  number of compoundings  per year

t  = the  number of years

A  =    10000  (  1  + .10  / 2)^(2 *1)    =   10000  ( 1.05)^2    =  $11025

Step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

you have to put the graph on here with the question

step-by-step explanation: