Solve each question (a, b, c) and show your work. Thank you <3

a) 112 ft.

b) 256 ft. and 3 seconds

c) 7 seconds

Step-by-step explanation:

a) The model rocket is lauched from a platform. To find the height of the platform, we need to find h when t = 0, because the rocket starts from the platform when no time has elapsed:

Therefore, the height of the platform is ft.

b) If you learned calculus before, we can find the maximum height easily. We take the derivative of h and set it equal to 0. Remember, the derivative of a function is simply the slope of it at an instantaneous point. At the maximum point of a function, it's slope equals to 0.

Ok! Let's set the derivative of h to 0!

We now know how long it takes for the rocket to reach maximum point (t represents seconds), but we also need to find the maximum height. We can simply plug our t=3 into the function of h, because t=3 is the point where the rocket reaches maximum height:

The maximum height of the rocket is ft and the rocket takes seconds to reach the height.

c) The rocket reaches the ground when h equals 0. We can set up the equation to solve for it:

However, time can never be negative.

Therefore, it takes the rocket seconds to reach the ground.

I hope this helps! Let me know if you have any questions :)

4.0 ft

step-by-step explanation:

4.0 ft

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb