What is the probability that 1 or 2 are rolled on a number cube with sides numbered 1, 2, 3, 4, 5, and 6?

Step-by-step explanation:

total sides = 6

p (rolling a 1) =

p (rolling a 2) =

Note:

or - add

and - multiply

∴

∴

hence, p (rolling a 1 or 2) =

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p