Find a diginacci sequence with no equal term to 11: quick answer please

uhh hope this helps

Step-by-step explanation:

A Diginacci sequence is created as follows.

• The first two terms are any positive whole numbers.

• Each of the remaining terms is the sum of the digits of the previous

two terms.

For example, starting with 5 and 8 the Diginacci sequence is

5, 8, 13, 12, 7, 10,. . .

The calculations for this example are

5 + 8 = 13, 8 + 1 + 3 = 12, 1+ 3 +1+ 2 = 7, 1 + 2 + 7 = 10.

a) List the first 26 terms of the Diginacci sequence above.

b) Find, with explanation, two starting terms for a Diginacci sequence

so that its 2021st term is 11.

c) Find, with explanation, a Diginacci sequence that has no term equal

to 11.

d) Find, with explanation, a sequence with two different starting terms

which contains five consecutive terms that are even and not all identical

Both 2 and 3 is correct.

b

step-by-step explanation:

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: