1. Many Alpine ski centers base their calculations of revenues and profits on the belief that the average skier ski’s four times a year with a population standard deviation of 2. To investigate this belief a random sample of 63 skiers was drawn and each participant was asked to report the number of times they skied last year. This yielded a mean of 4.84. Can we infer at the 10% significance level that the assumption of ski centers is wrong?

We cannot infer at the 10% significance level that the assumption of ski centers is wrong

Step-by-step explanation:

The null hypothesis for this question can be stated as  

Null hypothesis H0:  =4  

Alternate hypothesis Ha:  

The test is two tailed

Standard Deviation –  

 = 2

z=(4.84-4)/(2/sqrt(63))

=3.33

Z(0.1/2)=1.645 is less than Z =3.334

Hence, we will reject H0  

Hence, the average growth skier ski’s four times a year is not true  

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752