Let F be the radial force field F=xi+yj. Find the work done by this force along the following two curves, both which go from (0, 0) to (5, 25). (Compare your answers!) A. If C1C1 is the parabola: x=t, y=t2, 0≤t≤5x=t, y=t2 , 0≤t≤5, then ∫C1F⋅dr=?

B. If C2 is the straight line segment: x=5t2, y=25t2, 0≤t≤1x=5t2,  y=25t2, 0≤t≤1, then ∫C2F⋅dr=?​

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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