You have one each of $0.05, $0.10, $0.25, $1.00 and $2.00 coins in your wallet. How many different sums of money could you form by reaching into your wallet and pulling out some coins?

The correct answer is - 26 sums for pulling few coins.

Step-by-step explanation:

Given:

coins in the wallet = 5 ($0.05, $0.10, $0.25, $1.00 and $2.00)

Different sums of money = ?

Formula: Different combination of items can be calculated with the help of a formula of combination that is -

nCr = n! / ((n – r)! r!)

where, n = total number of items

r = number of item in a set

solution:

In this question number of set is not given only few mention so the sets could be 2 coins, 3 coins, 4 coins and 5 coins.

a. for set of 2 coins

= 5! / ((5 – 2)! 2!)

= 20/2

= 10 combination of sums

b. for the set of 3 coins

= 5! / ((5 – 3)! 3!)

= 10

C. for 4

= 5! / ((5 – 4)! !)

= 5

d. for 5 coins

only 1 sum

thus, the total types of different sums = 10+10+5+1

= 26.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925