The hypotenuse of a right triangle measures 20cm. The sum of the lengths of the other two sides is 28cm. Find the lengths of those two sides.

Step-by-step explanation:

Here, h = 20cmBy question, p + b = 28cmor, p = 28 - bUsing pythagoras theorem, h^2 =p^2 + b^220^2 = (28-b) ^2 + b^2400 = 28^2 -2x28xb + b^2 + b^256b = 784 - 400 + 2 b^20 = 2b^2 - 56b + 384 0 = 2 ( b^2 - 28b + 192)0 = b^2 - (16 + 12) b + 1920 = b^2 - 16b - 12b + 1920 = b (b - 16) - 12 (b - 16)0 = (b - 16) (b - 12)Either, b= 16Or,b = 12When b = 16,p = 28 - 16 = 12When b = 12,p = 28 - 12 = 16

3cm and 6 and 9 cm that a possibility of that question