2 cans of paint hold 64 and 125 oz. if the cans are similar cylinders and the smaller lid has an area of 18 find the area of the bigger lid.

The area of the bigger lid is approximately 29.2 square inches

Step-by-step explanation:

The given data are;

The volume held by one of the cans of paint, V₁ = 64 oz

The volume held by the other cans of paint, V₂ = 125 oz

The area of the smaller lid = 18 in²

Therefore,

The 64 Oz = The smaller can of paint

The 125 oz = The larger can of paint

The diameter of the smaller lid, d₁ = √(18 × 4/π) ≈ 4.787

The ratio of can volumes = (The ratio of can diameters)³

V₁/V₂ = (d₁/d₂)³

V₁/V₂ = 64/125

d₁/d₂ ≈ 4.787/d₂

64/125 = (4.787/d₂)³

4.787/d₂ = ∛(64/125) = 4/5

d₂ ≈ 4.878×5/4 = 6.0975

The area of the bigger lid, A₂ = π·d₂²/4

∴ A₂ = π × 6.0975²/4 ≈ 29.2

The area of the bigger lid, A₂ ≈ 29.2 in.²

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