a plane, initially traveling 150 mi/hr 100 east of north, suddenly enters a region where the wind is blowing at 50 mi/hr from southwest. what is the planes resultant direction

Velocity of plane is 100 mi/hr along northeast direction

Step-by-step explanation:

From the question it is given that Initial velocity of plane is 150 mi/hr along east north direction and wind is blowing at 50 mi/hr along southwest direction

since the velocity of wind and plane is exactly opposite

⇒ relative velocity of plane with respect to wind is given by

where  is the velocity of plane = 150mi/hr and  = velocity of wind = 50 mi/hr

Therefore,   =  alond northwest direction

Therefore, velocity of plane is 100 mi/hr along northeast direction

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

answer: it is a.,b.,d.

step-by-step explanation: