the sum of three numbers is 62 the second number is equal to the first number diminished by for the third number is four times the first ​

11, 7, 44

Step-by-step explanation:

a+b+c = 62

a-4 = b

c = 4×a

I think you meant "diminished by four", right ?

=>

a + a-4 + 4×a = 62

6×a - 4 = 62

6×a = 66

a = 11

=>

b = 11 - 4 = 7

c = 4×11 = 44

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.