Ahman has to pull in 25 m of rope to raise a 200-N weight 5 m using a pulley system. How much force does Ahman use to lift the weight?

The force Ahman uses to lift the load is 40 N

Step-by-step explanation:

Given;

force applied to the load, F₂ = 200 N

distance moved by the load, d₂ = 5 m

let the effort applied by Ahman, = F₁

distance moved by the effort, d₁ = 25 m

Apply the principle of conservation of energy;

Input work (J) = Output work (J)

F₁d₁ = F₂d₂

F₁ = (F₂d₂) / d₁

F₁ = (200 x 5) / 25

F₁ =  40 N

The force Ahman uses to lift the load is 40 N

b is the answer that makes most sense

step-by-step explanation:

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75