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Mathematics, 10.06.2021 22:40 sighgabbie

Solve for x: 3(x + 1) = βˆ’2(x βˆ’ 1) βˆ’ 4

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Solve for x: 3(x + 1) = βˆ’2(x βˆ’ 1) βˆ’ 4...
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