Which are the roots of the quadratic function f(q) = q2 – 125? Select two options. q = 55 StartRoot 5 EndRoot
q = -5Negative 5 StartRoot 5 Endroot
q = 33 StartRoot 5 Endroot
q = -3Negative 3 StartRoot 5 EndRoot
q = 2525 StartRoot 5 EndRoot

q =  ±5√5

Step-by-step explanation:

q² - 125 = 0

q² = 125

q = ±√(5 * 25)

q =  ±5√5

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this