Write the product in standard form. (2 + 3i)(2 - i)

(2+3i) (2-i)

2(2-i) + 3i(2-i)

4-2i+6i-3i^2

4+4i-3i^2

9514 1404 393

  7 +4i

Step-by-step explanation:

(2 +3i)(2 -i) = 2(2 -i) +3i(2 -i) = 4 -2i +6i +3 = 7 +4i

  i = √-1, so i^2 = -1. Otherwise the product is identical to what you would get if "i" were a variable.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!