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9514 1404 393

  see below

Step-by-step explanation:

It is convenient to sort the data. This aids counting the number of data points in each bin, and in figuring how to define the bins.

Here, there are 20 data values that range from 15 to 64, a rangel of 49. The chart in the problem statement suggests that 5 bins is a suitable number, so bins of width 10 would cover the range.

The bin boundary should always be defined so that no data point falls on the boundary. Here, we can define bins of width 10 that have boundaries that satisfy ...

  x = 10n +14.5 . . . . n = 0 to 5

Then your chart is filled as follows:

  interval, values, #

  14.5–24.5, {15, 19, 20}, 3

  24.5–34.5, {27, 30, 32, 32, 33}, 5

  34.5–44.5, {38, 39, 40, 44}, 4

  44.5–54.5, {45, 45, 48, 53, 54}, 5

  54.5–64.5, {60, 62, 64}

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29