Solve y^2-28y=-27

please show work :)

y = 1 or y = 27

Step-by-step explanation:

so first transpose -27 to the left side of the equation to make a quadratic equation.

y² - 28y + 27 = 0product = 27 , sum = -28 , factors = -1 , -27

( y² - y) ( -27y + 27)=0

y ( y - 1) - 27( y - 1)=0

( y - 1) ( y - 27)=0

y - 1 = 0 or y - 27 = 0

y = 1 or y = 27

10 b/c 5*2 =10

step-by-step explanation: