An NBA basketball court is rectangular in shape where the length is 2m less than twice the width. If the perimeter of the court is 86m, what are the dimensions (length and width) of the court?

Length = 28 m

Width = 15 m

Step-by-step explanation:

Court is rectangular in shape.

Now, we are told that;

Length is 2m less than twice the width(W) .

Thus;

Length; L = 2W - 2

We are told the perimeter is 86 m.

Formula for perimeter of a rectangle is;

P = 2(L + W)

Thus;

2((2W - 2) + W) = 86

Divide both sides by 2 to get;

(2W - 2) + W = 43

3W - 2 = 43

3W = 43 + 2

3W = 45

W = 45/3

W = 15 m

Thus; L = 2(15) - 2

L = 30 - 2

L = 28 m

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

me! what did you put for this question?

step-by-step explanation: