The mean weight of a domestic house cat is 8.9 pounds with a standard deviation of 1.1 pounds. The distribution of domestic house cat weights can reasonably be approximated by a normal distribution. What proportion of domestic house cats weigh less than 7 pounds?

0.0421

Step-by-step explanation:

We solve using the z score formula

z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean = μ = 8.9 pounds

σ is the population standard deviation = σ = 1.1 pounds

For x < 7 pounds

z = 7 - 8.9/1.1

= -1.72727

Probability value from Z-Table:

P(x<7) = 0.042059

Therefore, the proportion of domestic house cats weigh less than 7 pounds is

0.042059

Approximately = 0.0421

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!